Question

subtract second expression from the first expression
4pq- 6p²- 2q²,3p²-q² dio it full explanation​

Answer 1

Answer:

1p2-2q2

Step-by-step explanation:

4p2-2q2,3p2-q2

=(4p2-3p2),(2q2-q2)

=1p2-2q2

Answer 2

Answer:

Step-by-step explanation:

Given,

1st expression = 4pq - 6p^2 - 2q^2

Rearrange 1st expression = - 6p^2 - 2q^2 + 4pq

2nd expression = 3p^2 - q^2

Now subtract 2nd expression from 1st expression, we have

= ( - 6p^2 - 2q^2 + 4pq ) - (3p^2 - q^2 )

= ( - 6p^2 - 3p^2 ) + (- 2q^2 + q^2) + 4pq

= - 9p^2 - q^2 + 4pq