Math, asked by mathsexpertme1234, 1 month ago

subtract tha sum of (-2/3and-7/9)from the sum of (8/3and-5/18)

Answers

Answered by Anonymous
0

Answer:

answer

Step-by-step explanation

answer 23/6 make all the denominators same and then solve

Answered by prachidhruw
0

Answer:

answer is -23/6

Step-by-step explanation:

lets first add (-2/3and-7/9)

so, here I multiplied -2/3 with 3 to equalise their denominator.

 \frac{ - 2}{3}  +  \frac{ - 7}{9}  \times \frac{ - 2}{3}  \times  \frac{3}{3}  =  \frac{ - 6}{9}  \\  \frac{ - 6}{9}  +   \frac{ - 7}{9}  =  \frac{-13}{9}

now, add the fraction (8/3and-5/18),

 \frac{8}{3}  +  \frac{ - 5}{18} \\  \frac{8}{3}  \times  \frac{6}{6}  =  \frac{48}{18}  \\  \frac{48}{18}  +  \frac{ - 5}{18}  =  \frac{43}{18}

now, subtract both the sums,

(-13/9) - (43/18) = -23/6

the answer came 2/3 , as I shortened it as,

6 × 2 = 12 and 6 × 3 = 18.

hope this answer helps you.

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