Question

Subtract the additive inverse of (−3/5+2/3) from the multiplicative inverse of (1/4−7/12)

Answer 1

Answer:

1/15 and -7/6

additive inverse = -1/15.

multiplicative inverse = -6/7

➡️ according to the question,

➡️ -6/7 - (-1/15)

➡️ -6/7 + 1/15

➡️ -90 + 7 / 105

➡️ -83/105 ans.

Step-by-step explanation:

hope it helps ✔✔

Answer 2

Step-by-step explanation:

Given that: Subtract the additive inverse of (−3/5+2/3) from the multiplicative inverse of (1/4−7/12)

Solution:

First of all write the additive inverse of (-3/5+2/3)

Additive inverse of a is -a.

So, additive inverse of (-3/5+2/3) is (3/5-2/3)

Now find multiplicative inverse of (1/4−7/12)

As multiplicative inverse of a is 1/a.

First solve (1/4−7/12) and simplified

$\frac{1}{4}-\frac{7}{12}=\frac{3-7}{12}\\\\=\frac{-4}{12}=>\frac{-1}{3}$

Multiplicative inverse of -1/3 is -3.

Now subtract additive inverse from multiplicative inverse.

$-3-\bigg(\frac{3}{5}-\frac{2}{3}\bigg)\\\\=>\frac{-45-9+10}{15}\\\\=>\frac{-44}{15}$

Thus,Subtraction of the additive inverse of (−3/5+2/3) from the multiplicative inverse of (1/4−7/12) is -44/15.

Hope it helps you.