Subtract the additive inverse of 5/6 from the multiplicative inverse of -5/7×14/15
Answers
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Step-by-step explanation:
The required number is \frac{-2}{3}
3
−2
Step-by-step explanation:
To find : Subtract the additive inverse of \frac{5}{6}
6
5
from the multiplicative inverse of -\frac{5}{7}\times \frac{14}{15}−
7
5
×
15
14
?
Solution :
The additive inverse is -a+a=0−a+a=0
i.e. the additive inverse of \frac{5}{6}
6
5
is
-\frac{5}{6}−
6
5
The multiplicative inverse is a\times \frac{1}{a}=1a×
a
1
=1
i.e. the multiplicative inverse of -\frac{5}{7}\times \frac{14}{15}−
7
5
×
15
14
is
-\frac{7}{5}\times \frac{15}{14}−
5
7
×
14
15
Now, The required number is subtraction of the additive inverse from the multiplicative inverse
n=(-\frac{7}{5}\times \frac{15}{14})-(-\frac{5}{6})n=(−
5
7
×
14
15
)−(−
6
5
)
n=-\frac{3}{2}+\frac{5}{6}n=−
2
3
+
6
5
n=\frac{-9+5}{6}n=
6
−9+5
n=\frac{-4}{6}n=
6
−4
n=\frac{-2}{3}n=
3
−2
Therefore, The required number is \frac{-2}{3}
3
−2