Question

Subtract the additive inverse of 5/6 from the multiplicative inverse of -5/7×14/15

Answer 1

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Answer 2

Step-by-step explanation:

The required number is \frac{-2}{3}

3

−2

Step-by-step explanation:

To find : Subtract the additive inverse of \frac{5}{6}

6

5

from the multiplicative inverse of -\frac{5}{7}\times \frac{14}{15}−

7

5

×

15

14

?

Solution :

The additive inverse is -a+a=0−a+a=0

i.e. the additive inverse of \frac{5}{6}

6

5

is

-\frac{5}{6}−

6

5

The multiplicative inverse is a\times \frac{1}{a}=1a×

a

1

=1

i.e. the multiplicative inverse of -\frac{5}{7}\times \frac{14}{15}−

7

5

×

15

14

is

-\frac{7}{5}\times \frac{15}{14}−

5

7

×

14

15

Now, The required number is subtraction of the additive inverse from the multiplicative inverse

n=(-\frac{7}{5}\times \frac{15}{14})-(-\frac{5}{6})n=(−

5

7

×

14

15

)−(−

6

5

)

n=-\frac{3}{2}+\frac{5}{6}n=−

2

3

+

6

5

n=\frac{-9+5}{6}n=

6

−9+5

n=\frac{-4}{6}n=

6

−4

n=\frac{-2}{3}n=

3

−2

Therefore, The required number is \frac{-2}{3}

3

−2

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