Question

Subtract the additive inverse of 5/6 from the multiplicative inverse of -5/7*14/15

Answer 1

go through the solution step by step

Answer 2

Answer:

The required number is $\frac{-2}{3}$

Step-by-step explanation:

To find : Subtract the additive inverse of $\frac{5}{6}$ from the multiplicative inverse of $-\frac{5}{7}\times \frac{14}{15}$ ?

Solution :

The additive inverse is $-a+a=0$

i.e. the additive inverse of $\frac{5}{6}$ is

$-\frac{5}{6}$

The multiplicative inverse is $a\times \frac{1}{a}=1$

i.e. the multiplicative inverse of $-\frac{5}{7}\times \frac{14}{15}$ is

$-\frac{7}{5}\times \frac{15}{14}$

Now, The required number is subtraction of the additive inverse from the multiplicative inverse

$n=(-\frac{7}{5}\times \frac{15}{14})-(-\frac{5}{6})$

$n=-\frac{3}{2}+\frac{5}{6}$

$n=\frac{-9+5}{6}$

$n=\frac{-4}{6}$

$n=\frac{-2}{3}$

Therefore, The required number is $\frac{-2}{3}$