subtract the additive inverse of 7/8 from the multiplication inverse of -5/7×14/3
Answers
Answered by
35
additve inverse of 7/8 is -7/8
multiplicative inverse of -5/7×14/3 is -3×7/5×14
=-3/10
-3/10-(-7/8)=-3/10+7/8
=-0.3+0.875=-23/40
multiplicative inverse of -5/7×14/3 is -3×7/5×14
=-3/10
-3/10-(-7/8)=-3/10+7/8
=-0.3+0.875=-23/40
ManPreet2004:
Its answer is -23/40
what is the answer
thanks
it's ok
Answered by
15
Additive inverse is nothing but opposite sign i.e, + or -
ofa number.
a+(-a) = (-a)+(a) = 0
Multiplicative inverse is nothing but reciprocal of a number.
a×(1/a) = 1 = (1/a)×(a)
Additive inverse of 7/8 = -7/8
Multiplicative inverse of -5/7×14/3 = -70/21
= -21/70
= -7/8 - (-21/70)
= -7/8 + 21/70
= 7/8 - 21/70
= 245-84/280
= 161/280
ofa number.
a+(-a) = (-a)+(a) = 0
Multiplicative inverse is nothing but reciprocal of a number.
a×(1/a) = 1 = (1/a)×(a)
Additive inverse of 7/8 = -7/8
Multiplicative inverse of -5/7×14/3 = -70/21
= -21/70
= -7/8 - (-21/70)
= -7/8 + 21/70
= 7/8 - 21/70
= 245-84/280
= 161/280
Similar questions