Question

subtract the difference of 20/3 and 30/6 from the difference of 4 and 7/3​

Answer 1

Answer:

Answer:

\frac{20 \times 2 + 31 - 4 \times 6 + 7 \times 2}{6}620×2+31−4×6+7×2

= \frac{40 + 31 - 24 - 14}{6}=640+31−24−14

= \frac{71 - 38}{6}=671−38

\frac{33}{6} =5.5