Question

subtract the difference of 20/3and 31/6 from the difference of 4 and 7/3
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Answer 1

Answer:

$\frac{20 \times 2 + 31 - 4 \times 6 + 7 \times 2}{6}$

$= \frac{40 + 31 - 24 - 14}{6}$

$= \frac{71 - 38}{6}$

$\frac{33}{6} = 5.5$

Step-by-step explanation:

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Answer 2

Answer:

20/3= 40/6 so, 40/6-31/6=9/6which is equal to 3/2 and 4-7/3 can be written as 4/1-7/3= 5/3 now the required and is 5/3- 3/2=1/6