Question

Subtract the equation (3 = a + d) from the equation (3 = a + 3d) and find out a.

Answer 1

Answer:

Value of a is 3

Step-by-step explanation:

$a + d-3=0----(1)\\ \\ a + 3d-3=0----(2)$

We have to subtract equation (1) from equation (2)

$(a + 3d-3-(a + d-3)=0\\ \\ a + 3d-3-a - d+3=0\\ \\ 2d=0\\ \\ d=0$

Putting value of d in equation (1),

          $a+0-3=0\\ \\ a=3$