Question

subtract the first expression from the second 1/3x³y + 1/2yx² + 1/6x²y², 2/3xy³ + 1/2xy² + 1/6y²x² + 1/3yx³​

Answer 1

Answer:

Given First expression is x+2y+z

Second expression is −x−y−3z

Subtracting second expression from first one will give x+2y+z+x+y+3z=2x+3y+4z