Question

subtract the first polynomial from the second polynomial . plzzz​

Answer 1

Answer:

check solution

Step-by-step explanation:

we need to substract 1-a⁴ from 3a+2a²+3a³-4a⁴

so 3a+2a²+3a³-4a⁴ -(-a⁴+1)

i.e.

3a+2a²+3a³-4a⁴+a⁴-1

3a+2a²+3a³-3a⁴-1

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Answer 2

The expression is $3a+2a^{2}+3a^{3}-3a^{4}-1$.

Step-by-step explanation:

The two polynomials are:

$P(a)=1-a^{4}\\Q(a)=3a+2a^{2}+3a^{3}-4a^{4}$

Compute the value of Q (a) - P (a) as follows:

$Q(a)-P(a)=(3a+2a^{2}+3a^{3}-4a^{4})-(1-a^{4})$

                    $=3a+2a^{2}+3a^{3}-4a^{4}-1+a^{4}\\=3a+2a^{2}+3a^{3}-3a^{4}-1$

Thus, the expression is $3a+2a^{2}+3a^{3}-3a^{4}-1$.