Question

Subtract the following expression (3 Points) [92−2−42]−[42−3+22][9x2−2xy−4y2]−[4x2−3xy+2y2] (−3)(3+10)(x−3y)(3x+10y) 52+−625x2+xy−6y2 3(−3)(4+3)
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Answer 1

Step-by-step explanation:

First, adding 3x

2

+5xy+7y

2

+3 and 2x

2

−4xy−3y

2

+7, we have

= 3x

2

+5xy+7y

2

+3+2x

2

−4xy−3y

2

+7

= 5x

2

+xy+4y

2

+10

Now,

Subtracting 5x

2

+xy+4y

2

+10 from 9x

2

−8xy+11y

2

= (9x

2

−8xy+11y

2

)−(5x

2

+xy+4y

2

+10)

= 9x

2

−8xy+11y

2

−5x

2

−xy−4y

2

−10

= 4x

2

−9xy+7y

2

−10