Question

subtract the following
vii. a3 + b3 + c3 – 3abc from 7abc -3a3 +
5b^3-c^3
​

Answer 1

Answer:

Step-by-step explanation:f a + b + c = 0

Then,

a + b + c = 0

a + b = - c -- (I)

(a + b)^3 = (- c)^3

a^3 + b^3 + 3ab (a + b) = - c^3

from equation (I) a + b = - c

a^3 + b^3 + 3ab (- c) = - c^3

a^3 + b^3 - 3abc = - c^3

a^3 + b^3 + c^3 = 3abc

Hence,

a^3 + b^3 + c^3 ‘not equal’ 0

but,

a^3 + b^3 + c^3 ‘equal’ 3abc

Answer 2

$7abc - 3 {a}^{3} + 5 {b}^{3} - {c}^{3} - \\ ( {a}^{3} + {b}^{3} + {c}^{3} - 3abc )$

$7abc - 3 {a}^{3} - 5 {b}^{3} - {c}^{3} - \\ {a}^{3} - {b}^{3} - {c}^{3} + 3abc$

$- 3 {a}^{3} - {a}^{3} - 5 {b}^{3} - {b}^{3} - \\ {c}^{3 } - {c}^{3} + 7abc + 3abc$

$- 4 {a}^{3} - 6 {b}^{3} - 2 {c}^{3} + 10abc$

hope it helps you ♡♡♡♡♡♡♡♡