Math, asked by anilkir7, 9 months ago

subtract the largest number of 6 digits formed by 2,4 and 5 from the largest nymber 7 digit firmed ed by 1,0 and 2. (repetition of digits is allowed)​

Answers

Answered by mysticd
13

 i)Largest \:6 \: digit \: number \:formed \: by

 2,4 \:and \: 5 \: is \: \blue { 5,55,542 }

 ii)Largest \:7 \: digit \: number \:formed \: by

 1,0 \:and \: 2 \: is \: \pink { 22,22,210}

/* According to the problem given */

 Largest \: 7 \:digit \: number - Largest \:6 \:digit \: number

 = 2222210 - 555542

 = 1666668

Therefore.,

 \red{ Required \:number } \green { = 16,66,668 }

•••♪

Answered by Anonymous
2

Given :

  • largest number of 6 digits formed by 2,4 and 5

  • largest nymber 7 digit formed by 1,0 and 2

To Find :

  • their difference

Solution :

largest 6 digit no. = 5,55,542

_____________________

largest 7 digit no. = 22,22,210

_____________________

their difference = 22,22,210 - 5,55,542

⇒ their difference = 16,66,668

their difference is 16,66,668

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