Question

Subtract the product of 14y² + 2xy - 5x² and 2x + 6y from the product of 11x’ - 6xy + 7y and
6xy - 11.​

Answer 1

Answer:

Step-by-step explanation:

Solution:

(6xy) × (-3x²y³)

= {6 × (-3)} × {xy × x²y³}

= -18x1+2

1

+

2

y1+3

1

+

3

= -18x³y⁴.

(ii) 7ab², -4a²b and -5abc

Solution:

(7ab²) × (-4a²b) × (-5abc)

= {7 × (-4) × (-5)} × {ab² × a²b × abc}

= 140 a1+2+1

1

+

2

+

1

b2+1+1

2

+

1

+

1

c

= 140a⁴b⁴c.