Math, asked by evan23, 1 year ago

subtract the product of 2 upon 3 and minus 5 upon 7 solve the sum of 7 upon 9 and minus 11 upon 18​

Answers

Answered by alarmsdisturb
43

Answer:

Step-by-step explanation:

Thr first two fractions are 2/3 and -5/7

We are supposed to find the product

So it would be 2×(-5) / 3×7

= -10/21

.

The second thing is to add 7/9 and -11/18

To add , we need to have the same denominators

To get that , we multiply (7/9)×2

We get , 14/18

When we add the fractions ,

14+(-11) / 18

= 3/18

Which if further simplified gives the answer as 1/6

.

Hope this helps :)

Answered by rajubrijpalgautam
32

multiply the sum of 2 upon 9 and 3 upon 11 by the by the sum of 5upon and 7 upon 8

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