subtract the product of (x+2y)and (2x-3y+7) from product of (2x-3y) and (x-y-6z)
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(x+2y)(2x-3y+7)=2x^2-3xy+7x+4xy-6y^2+14y=2x^2-6y^2+7x+14y+xy
(2x-3y)(x-y-6z)=2x^2-2xy-12xz-3xy+3y^2+6yz=2x^2+3y^2-5xy-12xz+6yz
their difference is
9y^2-6xy-12xz+6yz-7x-14y
(2x-3y)(x-y-6z)=2x^2-2xy-12xz-3xy+3y^2+6yz=2x^2+3y^2-5xy-12xz+6yz
their difference is
9y^2-6xy-12xz+6yz-7x-14y
Answered by
1
[(x+2y)(2x-3y+7)]-[(2x-3y)(x-y-6z)]
(2x²-3xy+7x+4xy-6y²+14y)-(2x²-2xy-12xz-3xy+3y²-18yz)
2x²-3xy+7x+4xy-6y²+14y-2x²+2xy+12xz+3xy -3y²+18yz
7x+6xy+9y²+14y+12xz+18yz Answer
(2x²-3xy+7x+4xy-6y²+14y)-(2x²-2xy-12xz-3xy+3y²-18yz)
2x²-3xy+7x+4xy-6y²+14y-2x²+2xy+12xz+3xy -3y²+18yz
7x+6xy+9y²+14y+12xz+18yz Answer
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