Question

Subtract the reciprocal of 3/5 from the additive inverse of 4/7.​

Answer 1

$\Large{\boxed{\red{Answer:-{\frac{47}{21}}}}}$or $\Large{\boxed{\red{2{\frac{5}{21}}}}}$

Reciprocal of $\frac{3}{5}$ = $\frac{5}{3}$

Additive inverse of $\frac{4}{7}$ = $\frac{-4}{7}$

So, the numbers are, $\frac{5}{3}$ and $\frac{-4}{7}$

So, Subtract $\frac{5}{3}$ from $\frac{-4}{7}$

➡ $\frac{-4}{7}$ - $\frac{5}{3}$

So, find LCM of both numbers denominators.

➡ LCM of 7 and 3 = 21

So, multiply both numbers to get their denominator 21.

➡ $\frac{-4}{7}$×$\frac{3}{3}$=$\frac{-12}{21}$

➡ $\frac{5}{3}$×$\frac{7}{7}$=$\frac{35}{21}$

Now, $\frac{-4}{7}$is$\frac{-12}{21}$ and $\frac{5}{3}$is $\frac{35}{21}$

Now we can subtract :-

➡$\frac{-12}{21}$-$\frac{35}{21}$

➡$\frac{-12-(+35)}{21}$

➡$\frac{-12-35}{21}$

➡$\frac{+47}{21}$

▶$\large{\boxed{\green{Answer:\:2{\frac{5}{21}}\:or\::{\frac{47}{21}}}}}$