subtract the second polynomial from first : 2ab²+3a²b-2ab, 8ab²-3a²b+4ab. plases solve plases
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Answered by
1
6ab( a - b - 1)
Step-by-step explanation:
(2ab^2 + 3a^2b - 2ab) - (8ab^2 -3a^2b + 4ab)
= 2ab^2 - 8ab^2 + 3 a^2b + 3 a^2b - 2ab - 4ab
= - 6ab^2 + 6a^2b - 6ab
= 6ab( a - b - 1 )
Answered by
0
(2ab² + 3a²b - 2ab) - (8ab² - 3a²b + 4ab)
= 2ab² - 8ab² + 3a²b + 3a²b - 2ab - 4ab
= -6ab² + 3a²b - 6ab
= 3a²b - 6ab² - 6ab
It can be rewritten (by dividing all figures by 3) as:
a²b - 2ab² - 2ab
= ab (a - 2b - 2)
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