Question

Subtract the square of 28 from the square of 29 without actually calculating the squares. ​

Answer 1

Answer:

Given,

We need to Subtract the square of 28 from the square of 29 without actually calculating the squares.

Using the formula

${x}^{2} - {y}^{2} = (x + y)(x - y)$

We get....

$= > {(29)}^{2} - {(28)}^{2} \\ = > (29 + 28)(29 - 28) \\ = > 57 \times 1 \\ = > 57.$

Answer 2

Simply by using algebraic identity

X^2-y^2=(x+y)(x-y)

So, it is 28^2-29^2=(28+29)(28-29)

=57X1

=57

So, your answer is 57.