Question

Subtract the sum 3x² + 2y², - x²-4y²+2xy and 6xy + 2x²-3y², subtract -5x² + 2y²-3xy.

Answer 1

Your question :

From the sum of 3x² + 2y², -x² - 4y² + 2xy and 6xy + 2x² - 3y²,

subtract - 5x² + 2y²-3xy.
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Solution :

First we add

3x² + 2y², -x²- 4y² + 2xy and 6xy + 2x² -3y².

3x² + 2y² - x² - 4y² + 2xy + 6xy + 2x² - 3y²

= ( 3x² - x² + 2x²) + ( 2y² - 4y² - 3y² ) + ( 2xy + 6xy)

= 4x² - 5y² + 8xy

Now, we subtract

-5x² + 2y² - 3xy. from 4x² - 5y² + 8xy

( 4x² - 5y² + 8xy) - ( -5x² + 2y² - 3xy)

= 4x² - 5y² + 8 xy + 5x² - 2y² + 3xy [ Sign of terms changed ]

= ( 4x² + 5x² ) + ( -5y² - 2y² ) + ( 8xy + 3xy) [ Like terms are grouped ]

= 9x² - 7y² + 11xy [ We add like terms ]

Answer 2

Answer:

Your question :

From the sum of 3x² + 2y², -x² - 4y² + 2xy and 6xy + 2x² - 3y²,

subtract - 5x² + 2y²-3xy.

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Solution :

First we add

3x² + 2y², -x²- 4y² + 2xy and 6xy + 2x² -3y².

3x² + 2y² - x² - 4y² + 2xy + 6xy + 2x² - 3y²

= ( 3x² - x² + 2x²) + ( 2y² - 4y² - 3y² ) + ( 2xy + 6xy)

= 4x² - 5y² + 8xy

Now, we subtract

-5x² + 2y² - 3xy. from 4x² - 5y² + 8xy

( 4x² - 5y² + 8xy) - ( -5x² + 2y² - 3xy)

= 4x² - 5y² + 8 xy + 5x² - 2y² + 3xy [ Sign of terms changed ]

= ( 4x² + 5x² ) + ( -5y² - 2y² ) + ( 8xy + 3xy) [ Like terms are grouped ]

= 9x² - 7y² + 11xy [ We add like terms ]

Step-by-step explanation: