Subtract the sum of 1/2, 1/3 and 1/5 from the sum of 3/2 , 2/3 and 1.
Answers
Answered by
1
To save time, just find that multiple, if I’m not mistaken it’s 84. Multiple every fraction by X / X such that you get an 84. For example, for 5/7, divide 84 by 7 to get 12, so multiply that fraction by 12/12 (which is 1, not changing the number) yielding -60/84 (this is the same number as 5/7, just written with respect to 84ths, just like percents are just fractions with the denominator of 100. Per cent, makes enough sense right?
-5/7 + -8/3 is just -60/84 + -224/84 = –284/84
5/2 + -11/12 becomes 210/84 + -77/84 = 133/84
The wording is important “subtract the [] from the []” so we know to use the second sum as the base and subtract the former sum.
133/84 - (-284/84) = 417/84 = 139/28
-5/7 + -8/3 is just -60/84 + -224/84 = –284/84
5/2 + -11/12 becomes 210/84 + -77/84 = 133/84
The wording is important “subtract the [] from the []” so we know to use the second sum as the base and subtract the former sum.
133/84 - (-284/84) = 417/84 = 139/28
Answered by
1
Step-by-step explanation:
see the attachment. I think this is the answer.
Attachments:
Similar questions