Question

subtract the sum of 1/4and-3/8from the additive inverse of-3/8-(-2/7)

Answer 1

Here is ur answer........

Answer 2

$the \: sum \: of \: \frac{1}{4} \: and \: \frac{ - 3}{8} \\ \\ = \frac{1}{4} + \frac{ - 3}{8} \\ \\ = \frac{2 + - 3}{8} \\ \\ = \frac{ - 1}{8} \\ \\ \\ \\ the \: additive \: inverse \: of \: \\ \frac{ - 3}{8} + \frac{2}{7} \\ \\ = \frac{ - 21 + 16}{56} \\ \\ = \frac{ - 5}{56} \\ is \: \frac{5}{56}$




now what we have to do is to subtract
$\frac{ - 1}{8} from \frac{5}{56 }$

so
$= \frac{5}{56} - - \frac{1}{8} \\ \\ = \frac{5 + 7}{56} \\ \\ = \frac{12}{56}$