Subtract the sum of ( 11 - 8x^3 + x^4 ) and ( 2 + 8x^4 -3x^3 - x^2) from the sum of
( 5x^3-2x^4 - 3x^2 + 5) and ( 7x^3 - 8x^4 + 3x^2)
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Answers
Answer:
23x³ - 19x⁴ - 8 - x² ⇒ -19x⁴ + 23x³ - x² - 8
Step-by-step explanation:
The sum of (5x³-2x⁴ - 3x² + 5) and ( 7x³ - 8x⁴ + 3x²):
(5x³-2x⁴ - 3x² + 5) + (7x³ - 8x⁴ + 3x²)
⇒ 5x³ + 7x³ - 2x⁴ - 8x⁴ - 3x² + 3x² + 5
⇒ 12x³ - 10x⁴ + 5
∴The sum of (5x³-2x⁴ - 3x² + 5) and ( 7x³ - 8x⁴ + 3x²) is 12x³ - 10x⁴ + 5.
The sum of ( 11 - 8x³ + x⁴ ) and ( 2 + 8x⁴ -3x³ - x²):
(11 - 8x³ + x⁴ ) + (2 + 8x⁴ - 3x³ - x²)
⇒ 11 +2 - 8x³ - 3x³ + x⁴ + 8x⁴ - x²
⇒ 13 - 11x³ + 9x⁴ - x²
∴The sum of ( 11 - 8x³ + x⁴ ) and ( 2 + 8x⁴ -3x³ - x²) is 13 - 11x³ + 9x⁴ - x²
Now , (12x³ - 10x⁴ + 5) - (13 - 11x³ + 9x⁴ - x²)
⇒ 12x³ - 10x⁴ + 5 - 13 + 11x³ - 9x⁴ + x²
⇒ 12x³ + 11x³ - 10x⁴ - 9x⁴ + 5 - 13 - x²
⇒ 23x³ - 19x⁴ - 8 - x² = -19x⁴ + 23x³ - x² - 8
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