Question

Subtract the sum of 12a²b + 4ab - 6a² and 4a²b + 3ab - 2a² from (4) 2a²b + 3ab 8a​

Answer 1

Answer:

2ab^2 + 3a^2b-4ab

-8ab^2 + 2a^2b +3ab

+

6ab^2 + a^2b-7ab

Answer 2

Answer:

(4) 2a²b + 3ab + 8a - (12a²b + 4ab - 6a² + 4a²b + 3ab - 2a²)

(4) 2a²b + 3ab + 8a - (12a²b + 4a²b + 4ab + 3ab - 6a² - 2a²)

(4) 2a²b + 3ab + 8a - (16a²b + 4ab + 3ab - 6a² - 2a²)

(4) 2a²b + 3ab + 8a - (16a²b + 7ab - 6a² - 2a²)

(4) 2a²b + 3ab + 8a - (16a²b + 7ab - 8a²)

4 × 2a²b + 3ab + 8a - 16a²b - 7ab + 8a²

8a²b - 16a²b + 3ab - 7ab + 8a + 8a²

- 8a²b + 3ab - 7ab + 8a + 8a²

- 8a²b - 4ab + 8a + 8a²

(4) 2a²b + 3ab - 8a - (12a²b + 4ab - 6a² + 4a²b + 3ab - 2a²)

(4) 2a²b + 3ab - 8a - (12a²b + 4a²b + 4ab + 3ab - 6a² - 2a²)

(4) 2a²b + 3ab - 8a - (16a²b + 4ab + 3ab - 6a² - 2a²)

(4) 2a²b + 3ab - 8a - (16a²b + 7ab - 6a² - 2a²)

(4) 2a²b + 3ab - 8a - (16a²b + 7ab - 8a²)

4 × 2a²b + 3ab - 8a - 16a²b - 7ab + 8a²

8a²b - 16a²b + 3ab - 7ab - 8a + 8a²

- 8a²b + 3ab - 7ab + 8a - 8a²

- 8a²b - 4ab - 8a + 8a²

Step-by-step explanation:

Hope this will help you and you didn't mention any sign between 3ab and 8a so I have already solved the equation with both the signs. First equation is with addition sign and the second one is with subtraction sign. If yes please mark me as a brainliest.