Subtract the sum of (12ab – 10b 2 – 18a 2 ) and (9ab – 12b 2 + 14a 2 ) from the sum of (ab + 2b 2 ) and (3b 2 – a
Answers
Answer:
The solution for the given expression is - 5 a² - 27 b² + 20 ab
Step-by-step explanation:
Given as :
The expression is
12 ab - 10 b² - 18 a² ..........A
9 ab - 12 b² + 14 a² .........B
The sum of eq A and eq B
( 12 ab - 10 b² - 18 a² ) + ( 9 ab - 12 b² + 14 a² ) = (12 + 9) ab + ( - 10 - 12 )b² + (-18+14) a²
= 21 ab - 22 b² - 4 a² .....1
Again
The expression is
ab + 2 b² ..........C
3 b² - a² ..........D
The sum of eq C and D
( ab + 2 b² ) + ( 3 b² - a² ) = ab + (2 + 3) b² - a²
= ab + 5 b² - a² ......2
Now, Subtracting eq 1 from eq 2
So, ( 21 ab - 22 b² - 4 a²) - ( ab + 5 b² - a² ) = (21 - 1) ab + (-22 -5) b² + (-4 + 1)a²
= 20 ab - 27 b² - 5 a²
Hence, The solution for the given expression is - 5 a² - 27 b² + 20 ab Answer
Answer:
here is the answer..........
