Subtract the sum of 12ab−10b2 −18a2 and 9ab+12b2 +14a2 from the sum of ab+2b2 and 3b2 −a2
Answers
Answered by
40
Step-by-step explanation:
=((ab+2b2)+(3b2-a2))-((12ab-10b2-18a2)+(9ab+12b2+14a2))
=(ab+5b2-a2)-(21ab+2b2-4a2)
=(ab+5b2-a2-21ab-2b2+4a2)
=-20ab+3b2+3a2
Answered by
13
Step-by-step explanation:
12ab-10b2-18a2. ab+2b2
+9ab+12b2+14a2. 3b2-a2
= 21ab -2b2-4a2. =3ab3-2a2b2
difference
3ab3-2a2b2
--21ab-2b2-4a2
=-19ab3-2ab2-4a2
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