Math, asked by bhattsamarth2008, 3 months ago

Subtract the sum of 12ab-10b²-18a² and 9ab+12b²+14a² from the sum of ab+2b² and 3b²-a²​

Answers

Answered by ROHANBELDAR007
7

Step-by-step explanation:

Sum of 12ab-10b2 -18a2 and 9ab + 12b2 + 14a2 = 12ab – 10b2 – 18a2 + 9ab + 12b2 + 14a2 On combining the like terms, = 12ab + 9ab – 10b2 + 12b2 – 18a2 + 14a2 = 21 ab +2b2 – 4a2 Sum of ab + 2b2 and 3b2 – a2 = ab + 2b2 + 3b2 – a2 = ab + 5b2 – a2 Now, subtracting 21ab + 2b2 – 4a2 from ab + 5b2 – a2, we get = (ab + 5b2 – a2) – (21ab + 2b2 – 4a2) = ab+ 5b2 – a2 – 21ab – 2b2 + 4a2 On combining the like terms, = ab – 21ab + 5b2 – 2b2 – a2 + 4a2 = – 20ab + 3b2 + 3a2 = 3a2 + 3b2 – 20abRead more on Sarthaks.com - https://www.sarthaks.com/842671/subtract-the-sum-of-12ab-10b-2-18a-2and-9ab-12b-2-14a-2from-the-sum-of-ab-2b-2and-3b-2-a-2

Answered by vaibhavdantkale65
2

Answer:

Subtract the sum of 12ab-10b²-18a² and 9ab+12b²+14a² from the sum of ab+2b² and 3b²-a²

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