Question

Subtract the sum of 13x+4y−2zand −6z+6x−2yfrom the sum of2x+4y−8zand 4x–3y+z

Answer 1

Answer:

First we have to find the sum of 13x – 4y + 7z and – 6z + 6x + 3y Therefore, sum of (13x – 4y + 7z) and (–6z + 6x + 3y) = (13x – 4y + 7z) + (–6z + 6x + 3y) = (13x – 4y + 7z – 6z + 6x + 3y) = (13x + 6x – 4y + 3y + 7z – 6z) = (19x – y + z) Now we have to find the sum of (6x – 4y – 4z) and (2x + 4y – 7) = (6x – 4y – 4z) + (2x + 4y – 7) = (6x – 4y – 4z + 2x + 4y – 7) = (6x + 2x – 4z – 7) = (8x – 4z – 7) Now, required expression = (8x – 4z – 7) – (19x – y + z) = 8x – 4z – 7 – 19x + y – z = 8x – 19x + y – 4z – z – 7 = –11x + y – 5z – 7Read more on Sarthaks.com - https://www.sarthaks.com/682959/subtract-the-sum-of-13x-4y-7z-and-6z-6x-3y-from-the-sum-of-6x-4y-4z-and-2x-4y-7