Math, asked by rivekumar, 1 year ago

subtract the sum of 13x + 4Y + 7 z and 6z+ 6 X + 3 Y from the sum of 6x + 4y+ 4z and 2x + 4y + 7

Answers

Answered by Tkarthikeyangokul

1

=(13x+4y+7z+6z+6x+3y)- (6x+4y+4z+2x+4y+7)
=(19x+7y+13z)-(8x+8y+4z+7)
=19x+7y+13z-8x-8y-4z-7
=11x-y+9z-7

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