Question

Subtract the sum of 13x-4y+7z and-6 z+6x+3y from the sum of 6x-4y-4z and 2x+4y-7​

Answer 1

(6x-4y-4z)+(2x+4y-7)=8x-4z-7
(13x-4y+7z)+(-6z+6x+3y)=19x-y+z
(8x-4z-7)-(19x-y+z)=8x-4z-7-19x+y-z
=-11x-5z+y-7

Answer 2

Answer:

-11x + y - 5z - 7

Step-by-step explanation:

STEP 1: Find the sum of (13x-4y+7z) and (-6z+6x+3y)

(13x-4y+7z ) + (-6z+6x+3y)

= 13x - 4y + 7z - 6z + 6x + 3y

= 19x - y + z

STEP 2: Find the sum of (6x-4y-4z) and (2x+4y-7​)

(6x - 4y - 4z) + (2x + 4y - 7​)

= 6x - 4y - 4z+ 2x + 4y - 7​

= 8x - 4z - 7

STEP 3: Subtract  (19x - y + z) from (8x - 4z - 7)

(8x - 4z - 7) - (19x - y + z)

= 8x - 4z - 7 - 19x + y - z

= -11x + y - 5z - 7

Answer:-11x + y - 5z - 7