Math, asked by dhriti1810, 11 months ago

Subtract the sum of 13x - 4y + 7z and -6z + 6x + 3y from the sum of 6x - 4y - 4z and 2x + 4y - 7

Answers

Answered by singhseeema57
3

Answer:

- 11x - 3z - 7 - y

Step-by-step explanation:

First,

We have to add the both two equations together

=> 13x -4y + 7z

+ 6x +3y - 6z

19x - y + z

And

6x - 4y - 4z

+ 2x +4y - 7

8x - 4z - 7

Then,

We have to solve both the equations

=> 8x - 4z - 7

- 19x + z - y

- 11x - 3z - 7 - y

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Answered by Anonymous
4

~First we have to find the sum of 13x – 4y + 7z and – 6z + 6x + 3y

Therefore, sum of  \sf \big \:   (13x – 4y + 7z)  \: and \:  (–6z + 6x + 3y)

 \large \sf \: = (13x – 4y + 7z) + (–6z + 6x + 3y)

 \large \sf \: = (13x – 4y + 7z – 6z + 6x + 3y)

 \large \sf  = (13x + 6x – 4y + 3y + 7z – 6z)

 \large \sf \underline{= (19x – y + z)}

~Now we have to find the sum of (6x – 4y – 4z) and (2x + 4y – 7)

 \large \sf \: = (6x – 4y – 4z) + (2x + 4y – 7)

 \large \sf \:  = (6x – 4y – 4z + 2x + 4y – 7)

 \large \sf \:  = (6x + 2x – 4z – 7)

 \large \sf  \underline{\: = (8x – 4z – 7)}

~Now, required expression = (8x – 4z – 7) – (19x – y + z)

 \large \sf \: = 8x  \: – \:  4z \:  –  \: 7  \: – \:  19x + y \:  – \:  z

 \large \sf \: = 8x \:  –  \: 19x + y  \: – \:  4z \:  – \:  z  \: – \:  7

 \large \sf \underline{ \:  = – \: 11x + y \:  – \:  5z \:  –  \: 7}

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