Question

Subtract the sum of 13x - 4y + 7z and -6z + 6x + 3y from the sum of 6x - 4y - 4z and 2x + 4y - 7

Answer 1

$6x-4y-4z+2x+4y-7-(13x-4y+7z+(-6z)+6x+3y)=\\8x-4z-7-(19x-y+z)=\\8x-4z-7-19x+y-z=\\-11x+y-5z-7$

Answer 2

Answer:

13x-4y+7z-6z+6x+3y =19x-y+z

6x-4y-4z+2x+4y-7 =8x-4z-7

8x-4z-7-(19x-y+z) =8x-4z-7-19x+y-z = - 11x+y-5z-7