Question

Subtract the sum of 13x-4y+7z and -6z+6x+3y from the sum of 6x-4y-4z and 2x+4y-7.
please tell ans of ch algebraic expressions and identities class 8th

Answer 1

Answer:

(-11x +1y -12z)

Step-by-step explanation:

Let's add the expressions as first step.....

(13x -4y +7z) + (-6z +6x +3y) = (19x -1y +1z)............equation1

(6x -4y -4z) + (2x + 4y -7z) = (8x +0 -11z).............equation2

Now substract equation1 from equation2

(8x +0 -11z) - (19x -1y +1z) = (-11x +1y -12z)

Answer 2

Answer:

-11x - 3z + y - 7

Step-by-step explanation:

sum of first two equations is 19x-y+z

sum of other two equations is 8x-4z-7

and then calculate their difference .