Question

Subtract the sum of 2 5/12
and 3 3/4 from the sum of 7 1/3and 5 1/6???
​

Answer 1

Answer:

Step-by-step explanation:

(71/3 +51/6) - (25/12+33/4)

=(11.83+8.5) - (2.08+8.25)

=20.33 - 10.33

=10 [Answer]

Answer 2

Answer:

$6\frac{1}{3}$

Step-by-step explanation:

The sum of $2\frac{5}{12}$ and $3\frac{3}{4}$ is

$2\frac{5}{12} +3\frac{3}{4} =\frac{29}{12} +\frac{15}{4}$

$=\frac{29+45}{12}$

$=\frac{74}{12}$   ------(1)

The sum of $7\frac{1}{3}$ and $5\frac{1}{6}$ is

$7\frac{1}{3} +5\frac{1}{6} =\frac{22}{3} +\frac{31}{6}$

$=\frac{44+31}{6}$

$=\frac{75}{6}$    ------(2)

Now substracting (1) from (2)

$\frac{75}{6} -\frac{74}{12}$

$=\frac{150}{12} -\frac{74}{12}$

$=$ $\frac{150-74}{12}$

$=\frac{76}{12}$

$=6\frac{4}{12}$

$=6\frac{1}{3}$

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Answer 3

Answer:

$6\frac{1}{3}$

Step-by-step explanation:

The sum of $2\frac{5}{12}$ and $3\frac{3}{4}$ is

$2\frac{5}{12} +3\frac{3}{4} =\frac{29}{12} +\frac{15}{4}$

$=\frac{29+45}{12}$

$=\frac{74}{12}$   ------(1)

The sum of $7\frac{1}{3}$ and $5\frac{1}{6}$ is

$7\frac{1}{3} +5\frac{1}{6} =\frac{22}{3} +\frac{31}{6}$

$=\frac{44+31}{6}$

$=\frac{75}{6}$    ------(2)

Now substracting (1) from (2)

$\frac{75}{6} -\frac{74}{12}$

$=\frac{150}{12} -\frac{74}{12}$

$=$ $\frac{150-74}{12}$

$=\frac{76}{12}$

$=6\frac{4}{12}$

$=6\frac{1}{3}$

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