Question

Subtract the sum of 2a + 3b, a - 2b + c, - a + 2c and 4a + 2b - 5 from 6a - 4b + 8

Answer 1

This is the required answer. Please mark it as brainliest.

Answer 2

The required expression -7b-3c+13.

Step-by-step explanation:

We need to subtract the sum of 2a + 3b, a - 2b + c, - a + 2c and 4a + 2b - 5 from 6a - 4b + 8.

Sum of 2a + 3b, a - 2b + c, - a + 2c and 4a + 2b - 5  is

$(2a+3b)+(a-2b+c)+(-a+2c)+(4a+2b-5)$

Combine like terms.

$(2a+a-a+4a)+(3b-2b+2b)+(c+2c)-5$

$6a+3b+3c-5$

Subtract 6a+3b+3c-5 from 6a - 4b + 8.

$(6a-4b+8)-(6a+3b+3c-5)$

$6a-4b+8-6a-3b-3c+5$

On combining like terms we get

$(6a-6a)+(-4b-3b)+(-3c)+(8+5)$

$-7b-3c+13$

Therefore, the required expression -7b-3c+13.

#Learn more

Subtract the sum of 2a+3b,a-2b+c,-a+2c and 4a+2b-5 from 6a-4b+8.

https://brainly.in/question/14683981