Math, asked by popstarastha3581, 7 months ago

Subtract the sum of (2a – 3b) and (4a – 3b) from the second multiple of (a – 3b)

Answers

Answered by muskan3410
0

Answer:

sum of (2a-3b)+(4a-3b) = (6a-6b)

subtract from (a-3b)

(a-3b) - (6a-6b)

= -5a+3b

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