Question

. Subtract the sum of (-2a) +3b- c , a+b-c and 4a-3b-2c from 6a-4b+8 .​

Answer 1

Answer:

( - 2a + 3b - c ) + ( a + b - c ) + ( 4a - 3b - 2c ) = 3a + b - 4c

now let's subtract it from ( 6a - 4b + 8 )

( 6a - 4b + 8 ) - ( 3a + b - 4c ) = 3a - 5b + 4c + 8

this is your answer

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