Subtract the sum of 2a²- 3ab + 7 and 3a²- 6ab+ 3 from the sum of -9a²+ 2ab-4 and a²-6 ab +9
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Step-by-step explanation:
sum of ( 2a²-3ab+7 ) + ( 3a²-6ab+3 )
= 2a²+3a² - 3ab-6ab +7+3
= 5a²- 9ab + 10
sum of (-9a²+2ab-4 ) + ( a²-6ab+9 )
= -9a²+a² + 2ab-6ab - 4+9
= -8a²- 4ab + 5
differnce = -8a² - 4ab + 5 - (5a² - 9ab + 10)
= -8a² - 4ab + 5 - 5a² + 9ab - 10
= -8a²-5a² - 4ab+9ab + 5-10
= -13a² + 5ab - 5
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Answer:
Subtract the sum of 2a²- 3ab + 7 and 3a²- 6ab+ 3 from the sum of -9a²+ 2ab-4 and a²-6 ab +9
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