subtract the sum of 2a²-5b²+7c²+3ab and 3a²-2abc+b²-c² from 5a²-2abc+5c².
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Answer:
4b²-c²-3ab
Step-by-step explanation:
5a²-4b²+6c²-2abc+3ab from 5a²-2abc+5c²
5a²-2abc+5c²-(5a²-4b²+6c²-2abc+3ab)
5a²-2abc+5c²-5a²+4b²-6c²+2abc-3ab
4b²-c²-3ab
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