Subtract the sum of 2x - x^2 + 5 and 4x - 3+ 7x^2
from 5.
Answers
Answered by
27
sum of (2x - x² + 5) and (4x - 3 + 7x²) = (2x - x² + 5) + (4x - 3 + 7x²)
= 2x - x² + 5 + 4x - 3 + 7x²
= 2x + 4x - x² + 7x² + 5 - 3
= 6x + 6x² + 2
= 6x² + 6x + 2
now subtracting the sum from 5,
= 5 - (6x² + 6x + 2)
= 5 - 6x² - 6x - 2
= 5 - 2 - 6x² - 6x
= 3 - 6x² - 6x
= 6x² - 6x + 3
= 3(2x² - 2x + 1)
KvKt2217:
the equation is not equal to 0 so you cannot cancel out 3 and remove -ve sign .....
Answered by
7
Answer:
-6x²-6x+3. or. -3(2x²+2x-1)
Step-by-step explanation:
- =5-(2x-x²+5+4x-3+7x²)
- =5-(7x²-x²+4x+2x+5-3)
- =5-(6x²+6x+2)
- =5-6x²-6x-2
- =-6x²-6x+3
- =-3(2x²+2x-1)
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