Question

subtract the sum of 2x²-3x+4 and x²-x+5 from the sum -9x+3+5x² and -x+6+2x²​

Answer 1

Answer:

$sum \: of \: first \: two = 2 {x}^{2} - 3x + 4 + {x}^{2} - x + 5 \\ = 3 {x}^{2} - 4x + 9$

$2nd = - 9x + 3 + 5 {x}^{2} - x + 6 + 2 {x}^{2} \\ = 7 {x}^{2} - 10x + 9$

$now \\7{x}^{2}-10x + 9 - 3{x}^{2} +4x - 9 \\ = 4 {x}^{2} - 6x$