Question

Subtract the sum of -3/4 and 3/4 from the difference of -3/4 and 3/4 please explain step by step​

Answer 1

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Answer 2

$\huge\underline {\sf {Answer :}}$

According to the Question :-

We have to ,

• Subtract the sum of $\dfrac {-3}{4}$ and $\dfrac {3}{4}$from the difference of $\dfrac {-3}{4}$ and $\dfrac {3}{4}$.

That is ,

• $\left(\dfrac {-3}{4} + \dfrac {3}{4}\right) - \left(\dfrac {-3}{4} - \dfrac {3}{4}\right)$

$\dag$ Now substituting the values in the expression :-

= $\left(\dfrac {-3}{4} + \dfrac {3}{4}\right) - \left(\dfrac {-3}{4} - \dfrac {3}{4}\right)$

= $\left(\dfrac {-3+3}{4}\right) - \left(\dfrac {-3-3}{4} \right)$

= $\left(\dfrac {0}{4}\right) - \left(\dfrac {-6}{4} \right)$

= $\left(\dfrac {0-(-6)}{4} \right)$

= $\left(\dfrac {0 + 6)}{4} \right)$

= $\left(\dfrac {6}{4} \right)$

= $\left(\dfrac {3}{2} \right)$

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