Question

Subtract the sum of 3/4 and 3/8 from the sum of 2/3, 3/4 and 7/12.
please answer this question fast

Answer 1

Answer:

The answer is 1/2 in the simplified form.

Step-by-step explanation:

Answer 2

★ How to do :-

Here, we are given with three fractions to add and other three fractions to add. The obtained results should be subtracted by each other. So, first before subtracting them we should add those two fractions separately. Then the obtained results i.e, answers should be subtracted by each other. The other concepts used while solving this problem is LCM, which is least common multiple. It's used to convert the unlike fractions to like fractions.

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➤ Solution :-

${\tt \leadsto \bigg(\dfrac{2}{3} + \dfrac{3}{4} + \dfrac{7}{12} \bigg) - \bigg(\dfrac{3}{4} + \dfrac{3}{8} \bigg)}$

Here, we should solve the brackets one by one. So, let's solve the first bracket first and the second next.

${\tt \leadsto \dfrac{2}{3} + \dfrac{3}{4} + \dfrac{7}{12}}$

LCM of 3,4 and 12 is 12.

${\tt \leadsto \dfrac{2 \times 4}{3 \times 4} + \dfrac{3 \times 3}{4 \times 3} + \dfrac{7}{12}}$

${\tt \leadsto \dfrac{8}{12} + \dfrac{9}{12} + \dfrac{7}{12}}$

${\tt \leadsto \dfrac{8 + 9 + 7}{12} = \dfrac{24}{12}}$

Now, let's solve the second bracket.

${\tt \leadsto \dfrac{3}{4} + \dfrac{3}{8}}$

LCM of 4 and 8 is 8.

${\tt \leadsto \dfrac{3 \times 2}{4 \times 2} + \dfrac{3}{8}}$

${\tt \leadsto \dfrac{6}{8} + \dfrac{3}{8}}$

${\tt \leadsto \dfrac{6 + 3}{8} = \dfrac{9}{8}}$

Now, let's subtract both the answers.

${\tt \leadsto \dfrac{24}{12} - \dfrac{9}{8}}$

LCM of 12 and 8 is 24.

${\tt \leadsto \dfrac{24 \times 2}{12 \times 2} - \dfrac{9 \times 3}{8 \times 3}}$

${\tt \leadsto \dfrac{48}{24} - \dfrac{27}{24}}$

${\tt \leadsto \dfrac{48 - 27}{24} = \dfrac{21}{24}}$

${\tt \leadsto \cancel \dfrac{21}{24} = \dfrac{3}{8}}$

$\Huge\therefore$ The answer is ⅜.