Question

subtract the sum of 3/8 and 7/3 from the sum of 4/5 and 7/8​

Answer 1

Answer:

According to question

(⅘+⅞)–(⅜+7/3)

Equalising the denominators

{(4×8)/(5×8) + (7×5)/8×5)} – {(3×3)/(8×3) + (7×8)/(3×8)}

(32/40+35/40)–(9/24+56/24)

67/40 – 65/24

(67×24)/(40×24)–(65×40)/(24×40)

1608/960–2600/960

=> –992/960

= –496/480

= –248/240

= –124/120

= –62/60

=> –31/30Answer