Math, asked by Samy77, 1 year ago

Subtract the sum of 31 - 4m- 7n^2 and 21 + 3 m - 4n^2from the sum of 91+2m - 3n^2 and -31 +m + 4n^2

Answers

Answered by taniya55555
8
Here is your answer,

The sum of 31 - 4m-7n^2 and 21+3m-4n^2 is
= 51-m-11n^2

The sum of 91+2m-3n^2 and -31+m+4n^2 is
= 60+3m-n^2

The difference between 51-m-11n^2 and 60+3m-n^2 is 9+4m+10n^2.

Hope this helps you. Have a nice day!!
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