Question

subtract the sum of -36/11 and 49/22 from the sum of 33/8and -19/ 4​

Answer 1

$\frac{ - 36}{11} + \frac{49}{22} \\ = \frac{ - 72 + 49}{22} \\ = \frac{ - 23}{22} \\ \\ \frac{33}{8} + \frac{ - 19}{4} \\ = \frac{33 - 38}{8} \\ = \frac{ - 5}{8}$

ATQ,

$\frac{ - 5}{8} - \frac{ - 23}{22} \\ = \frac{ - 5 + 92}{88} \\ = \frac{87}{88}$

Be Brainly!!!!

Answer 2

Question :–

Subtract the sum of $\sf \frac{-36}{11}$ and $\sf \frac{49}{22}$ from the sum of $\sf \frac{33}{8}$ and $\sf \frac{-19}{ 4}$

Solution :–

We have to find the subtraction of the sum of $\sf \frac{-36}{11}$ and $\sf \frac{49}{22}$ from the sum of $\sf \frac{33}{8}$ and $\sf \frac{-19}{ 4}$

So,

First we have to find the sum of this :–

$\implies \frac{ - 36}{11} + \frac{49}{22}$

L.C.M. of 11 & 22 is 22 [refer to the 1st attachment]

$\implies \frac{ - 72 + 49}{22}$

$\implies \frac{ - 23}{22}$

So, First number of subtraction = $\sf \frac{-23}{22}$

Now, we have to find the sum of this :–

$\implies \frac{33}{8} + \frac{ - 19}{4}$

L.C.M. of 8 & 4 is 8 [refer to the 2nd attachment]

$\implies \frac{33 + ( - 38)}{8}$

$\implies \frac{ - 5}{8}$

So, the second number of subtraction = $\sf \frac{-5}{8}$

Now we subtract this two numbers :–

$\implies \frac{ - 23}{22} - \frac{ - 5}{8}$

L.C.M. of 22 & 8 is 184 [refer to the 3rd attachment]

$\implies \frac{ (- 92) - ( - 55)}{88}$

$\implies \frac{ - 92 + 55}{88}$

$\boxed{ \sf \frac{ - 37}{88}}$