Question

Subtract the sum of 3a+2b-5ab and 5b-6a+2ab from the sum of 9b-11ab and -4a+21ab.​

Answer 1

Answer:

{(9b-11ab)+(-4a+21ab)}-{(3a+2b-5ab)+(5b-6a+2ab)}

={9b-11ab-4a+21ab}-{3a+2b-5ab+5b-6a+2ab}

=9b-11ab-4a+21ab-3a-2b+5ab-5b+6a-2ab

=9b-2b-5b-11ab+21ab+5ab-2ab-4a-3a+6a

=2b+13ab-a

Step-by-step explanation:

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Answer 2

To subtract :  sum of $3a+2b-5ab$ and $5b-6a+2ab$ from the sum of $9b-11ab$ and $-4a+21ab$ .

Solution :

• Subtraction is the arithmetic operation of taking off difference between two numbers.
• To subtract given algebraic expression, we subtract like terms together
• Remove parenthesis by changing sign of terms in second bracket .

• Therefore we get ,  

• Sum of  $3a+2b-5ab$ and $5b-6a+2ab$

         $( 3a + 2b -5ab ) + (5b-6a +2ab ) \\= 3a + 2b -5ab +5b -6a +2ab \\= -3a +7b - 3ab$

• Sum of $9b-11ab$ and $-4a+21ab$

        $(9b-11ab ) + (-4a+21ab) \\= 9b- 11ab -4a +21ab \\= 9b -4a + 10ab$

• Now , subtracting sum of  $3a+2b-5ab$ and $5b-6a+2ab$ from sum of $9b-11ab$ and $-4a+21ab$  

        $(9b-4a + 10ab)- ( -3a + 7b -3ab )\\= 9b -4a +10ab + 3a -7b +3ab \\= 2b -a +13ab$

Hence , correct answer is $2b -a + 13ab$ .