Question

Subtract the sum of 3a + 2b – c  and 5b – 6a +2ab from the sum of   9b -11ab and -4a + 21ab

 

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Answer 1

Answer:

Answer is -a+2b+c-8ab

Answer 2

Given,

The two expressions: 3a + 2b – c  and 5b – 6a +2ab

And another pair: 9b -11ab and -4a + 21ab.

To find,

The value after subtracting the sum of 3a + 2b – c  and 5b – 6a +2ab from the sum of   9b -11ab and -4a + 21ab.

Solution,

The value after subtracting the sum of 3a + 2b – c  and 5b – 6a +2ab from the sum of   9b -11ab and -4a + 21ab will be (-a+2b+c+8ab).

We can easily solve this problem by following the given steps.

We will first solve the first pair of expressions which the sum of 3a + 2b – c  and 5b – 6a +2ab.

Note that the numbers with the same variables can be added or subtracted.

(3a + 2b – c) + (5b – 6a +2ab)

(3a-6a) + (2b+5b) -c+2ab

-3a+7b-c+2ab

Now, adding the second pair of expressions,

(9b -11ab) + (-4a + 21ab)

9b-4a+(21ab-11ab)

9b-4a+10ab

Now, subtracting -3a+7b-c+2ab from 9b-4a+10ab,

(9b-4a+10ab) - (-3a+7b-c+2ab)

9b-4a+10ab+3a-7b+c-2ab

(-4a+3a) +(9b-7b)+c +(10ab-2ab)

-a+2b+c+8ab

Hence, the value after subtracting the sum of 3a + 2b – c  and 5b – 6a +2ab from the sum of   9b -11ab and -4a + 21ab is (-a+2b+c+8ab).