Subtract the sum of 3a – 7b + 2c and 4a + 2b + 3c from the sum of 5a – 6b
and a – 4b + c.
Answers
Answered by
1
Answer.
-a-5b-4c
Step by step explanation
Answered by
2
HIIIIII
Answer:
= a + 5b + 4c
Step-by-step explanation:
Solution 1
Sum of 3a – 7b + 2c and 4a + 2b + 3c
3a – 7b + 2c + 4a + 2b + 3c = 3a + 4a -7b + 2b + 2c + 3c
= 7a - 5b + 5c
Solution 2
Sum of 5a – 6b and a – 4b + c
5a – 6b + a – 4b + c = 5a + a - 6b - 4b +c
= 6a - 10b + c
Difference = Solution 2 - Solution 1
Difference = 7a - 5b + 5c - (6a - 10b + c)
Difference = 7a - 5b + 5c - 6a + 10b - c
Difference = 7a - 6a - 5b + 10b + 5c - c
Difference = a + 5b + 4c
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